How to solve 4(2)^(2)+3(2)-1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4(2)^(2)+3(2)-1 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

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Question

$$4 { 2 }^{ 2 } +3(2)-1$$

Evaluate

$21$

Solution Steps

Calculate $2$ to the power of $2$ and get $4$.

$$4\times 4+3\times 2-1$$

Multiply $4$ and $4$ to get $16$.

$$16+3\times 2-1$$

Multiply $3$ and $2$ to get $6$.

$$16+6-1$$

Add $16$ and $6$ to get $22$.

$$22-1$$

Subtract $1$ from $22$ to get $21$.

$$21$$

Show Solution

Factor

$3\times 7$

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