How to solve 4(4)^(2)+3(4)-1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4(4)^(2)+3(4)-1 | Equatix

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a⋅(b-2)=3b

3(r+2s)=2t-4

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Question

$$4 { 4 }^{ 2 } +3(4)-1$$

Evaluate

$75$

Solution Steps

To multiply powers of the same base, add their exponents. Add $1$ and $2$ to get $3$.

$$4^{3}+3\times 4-1$$

Calculate $4$ to the power of $3$ and get $64$.

$$64+3\times 4-1$$

Multiply $3$ and $4$ to get $12$.

$$64+12-1$$

Add $64$ and $12$ to get $76$.

$$76-1$$

Subtract $1$ from $76$ to get $75$.

$$75$$

Show Solution

Factor

$3\times 5^{2}$

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