$$4 { a }^{ 3 } -1- { a }^{ 2 } +4a$$
$\left(4a-1\right)\left(a^{2}+1\right)$
$$a^{2}\left(4a-1\right)+4a-1$$
$$\left(4a-1\right)\left(a^{2}+1\right)$$
Show Solution
Hide Solution