How to solve 4(-1)^(2)+3(-1)-1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4(-1)^(2)+3(-1)-1 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4 { -1 }^{ 2 } +3(-1)-1$$

Evaluate

$0$

Solution Steps

Calculate $-1$ to the power of $2$ and get $1$.

$$4\times 1+3\left(-1\right)-1$$

Multiply $4$ and $1$ to get $4$.

$$4+3\left(-1\right)-1$$

Multiply $3$ and $-1$ to get $-3$.

$$4-3-1$$

Subtract $3$ from $4$ to get $1$.

$$1-1$$

Subtract $1$ from $1$ to get $0$.

$$0$$

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Factor

$0$

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