Question

$$4 { x }^{ 2 } =-20$$

Answer

x=sqrt(5)*IM,-sqrt(5)*IM

Solution


Divide both sides by \(4\).
\[{x}^{2}=-\frac{20}{4}\]
Simplify  \(\frac{20}{4}\)  to  \(5\).
\[{x}^{2}=-5\]
Take the square root of both sides.
\[x=\pm \sqrt{-5}\]
Simplify  \(\sqrt{-5}\)  to  \(\sqrt{5}\imath \).
\[x=\pm \sqrt{5}\imath \]