$$4 { x }^{ 2 } +12+9$$
$8x$
$$\frac{\mathrm{d}}{\mathrm{d}x}(4x^{2}+21)$$
$$2\times 4x^{2-1}$$
$$8x^{2-1}$$
$$8x^{1}$$
$$8x$$
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$4x^{2}+21$
$$4x^{2}+21$$