How to solve 4/5+-3/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4/5+-3/9 | Equatix

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$$4/5+-3/9$$

$\frac{7}{15}\approx 0.466666667$

Reduce the fraction $\frac{-3}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{4}{5}-\frac{1}{3}$$

Least common multiple of $5$ and $3$ is $15$. Convert $\frac{4}{5}$ and $\frac{1}{3}$ to fractions with denominator $15$.

$$\frac{12}{15}-\frac{5}{15}$$

Since $\frac{12}{15}$ and $\frac{5}{15}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-5}{15}$$

Subtract $5$ from $12$ to get $7$.

$$\frac{7}{15}$$

$\frac{7}{3 \cdot 5} = 0.4666666666666667$