How to solve 4/6 imes(1-6)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4/6\times(1-6) | Equatix

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$$4/6 \times (1-6)$$

$-\frac{10}{3}\approx -3.333333333$

Reduce the fraction $\frac{4}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{2}{3}\left(1-6\right)$$

Subtract $6$ from $1$ to get $-5$.

$$\frac{2}{3}\left(-5\right)$$

Express $\frac{2}{3}\left(-5\right)$ as a single fraction.

$$\frac{2\left(-5\right)}{3}$$

Multiply $2$ and $-5$ to get $-10$.

$$\frac{-10}{3}$$

Fraction $\frac{-10}{3}$ can be rewritten as $-\frac{10}{3}$ by extracting the negative sign.

$$-\frac{10}{3}$$

$-\frac{10}{3} = -3\frac{1}{3} = -3.3333333333333335$