Solve [4*25+2*25+15*[2*25-5*(36:6-2*2)]-24*25\ :(27:3+1)

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Question

$$[4\cdot25+2\cdot25+15\cdot[2\cdot25-5\cdot(36:6-2\cdot2)]-24\cdot25\}:(27:3+1)$$

Evaluate

$-26400$

Solution Steps

Multiply $4$ and $25$ to get $100$. Multiply $2$ and $25$ to get $50$.

$$100+50+15\left(2\times 5-5\times 6\left(-2\right)\times 2-4\times 25\left(2\times 3\times 3+1\right)\right)$$

Add $100$ and $50$ to get $150$.

$$150+15\left(2\times 5-5\times 6\left(-2\right)\times 2-4\times 25\left(2\times 3\times 3+1\right)\right)$$

Multiply $2$ and $5$ to get $10$.

$$150+15\left(10-5\times 6\left(-2\right)\times 2-4\times 25\left(2\times 3\times 3+1\right)\right)$$

Multiply $5$ and $6$ to get $30$.

$$150+15\left(10-30\left(-2\right)\times 2-4\times 25\left(2\times 3\times 3+1\right)\right)$$

Multiply $30$ and $-2$ to get $-60$.

$$150+15\left(10-\left(-60\times 2\right)-4\times 25\left(2\times 3\times 3+1\right)\right)$$

Multiply $-60$ and $2$ to get $-120$.

$$150+15\left(10-\left(-120\right)-4\times 25\left(2\times 3\times 3+1\right)\right)$$

The opposite of $-120$ is $120$.

$$150+15\left(10+120-4\times 25\left(2\times 3\times 3+1\right)\right)$$

Add $10$ and $120$ to get $130$.

$$150+15\left(130-4\times 25\left(2\times 3\times 3+1\right)\right)$$

Multiply $4$ and $25$ to get $100$.

$$150+15\left(130-100\left(2\times 3\times 3+1\right)\right)$$

Multiply $2$ and $3$ to get $6$.

$$150+15\left(130-100\left(6\times 3+1\right)\right)$$

Multiply $6$ and $3$ to get $18$.

$$150+15\left(130-100\left(18+1\right)\right)$$

Add $18$ and $1$ to get $19$.

$$150+15\left(130-100\times 19\right)$$

Multiply $100$ and $19$ to get $1900$.

$$150+15\left(130-1900\right)$$

Subtract $1900$ from $130$ to get $-1770$.

$$150+15\left(-1770\right)$$

Multiply $15$ and $-1770$ to get $-26550$.

$$150-26550$$

Subtract $26550$ from $150$ to get $-26400$.

$$-26400$$

Show Solution

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