How to solve 4-3 3/9 + 3/9 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4-3 3/9 + 3/9 = | Equatix

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$$4 \cdot \frac { 3 } { 9 } + \frac { 3 } { 9 } =$$

$\frac{5}{3}\approx 1.666666667$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$4\times \frac{1}{3}+\frac{3}{9}$$

Multiply $4$ and $\frac{1}{3}$ to get $\frac{4}{3}$.

$$\frac{4}{3}+\frac{3}{9}$$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{4}{3}+\frac{1}{3}$$

Since $\frac{4}{3}$ and $\frac{1}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{4+1}{3}$$

Add $4$ and $1$ to get $5$.

$$\frac{5}{3}$$

$\frac{5}{3} = 1\frac{2}{3} = 1.6666666666666667$