$$4\frac{1}{3}+6\frac{1}{4}+\frac{1}{2}$$
$\frac{133}{12}\approx 11.083333333$
$$\frac{12+1}{3}+\frac{6\times 4+1}{4}+\frac{1}{2}$$
$$\frac{13}{3}+\frac{6\times 4+1}{4}+\frac{1}{2}$$
$$\frac{13}{3}+\frac{24+1}{4}+\frac{1}{2}$$
$$\frac{13}{3}+\frac{25}{4}+\frac{1}{2}$$
$$\frac{52}{12}+\frac{75}{12}+\frac{1}{2}$$
$$\frac{52+75}{12}+\frac{1}{2}$$
$$\frac{127}{12}+\frac{1}{2}$$
$$\frac{127}{12}+\frac{6}{12}$$
$$\frac{127+6}{12}$$
$$\frac{133}{12}$$
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$\frac{7 \cdot 19}{2 ^ {2} \cdot 3} = 11\frac{1}{12} = 11.083333333333334$
