How to solve +5 4 + 6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve +5 4 + 6 | Equatix

Question

$$4 \frac { 3 } { 11 } + [ 5 \frac { 5 } { 8 } \div \{ \frac { 3 } { 5 } + ( 4 \frac { 1 } { 5 } \times 2 \frac { 1 } { 6 } - 3 \frac { 1 } { 6 } ) \} ]$$

Evaluate

$\frac{44273}{8624}\approx 5.13369666$

Solution Steps

Multiply $4$ and $11$ to get $44$.

$$\frac{44+3}{11}+\frac{\frac{5\times 8+5}{8}}{\frac{3}{5}+\frac{4\times 5+1}{5}\times \frac{2\times 6+1}{6}-\frac{3\times 6+1}{6}}$$

Add $44$ and $3$ to get $47$.

$$\frac{47}{11}+\frac{\frac{5\times 8+5}{8}}{\frac{3}{5}+\frac{4\times 5+1}{5}\times \frac{2\times 6+1}{6}-\frac{3\times 6+1}{6}}$$

Multiply $5$ and $8$ to get $40$.

$$\frac{47}{11}+\frac{\frac{40+5}{8}}{\frac{3}{5}+\frac{4\times 5+1}{5}\times \frac{2\times 6+1}{6}-\frac{3\times 6+1}{6}}$$

Add $40$ and $5$ to get $45$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{4\times 5+1}{5}\times \frac{2\times 6+1}{6}-\frac{3\times 6+1}{6}}$$

Multiply $4$ and $5$ to get $20$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{20+1}{5}\times \frac{2\times 6+1}{6}-\frac{3\times 6+1}{6}}$$

Add $20$ and $1$ to get $21$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{21}{5}\times \frac{2\times 6+1}{6}-\frac{3\times 6+1}{6}}$$

Multiply $2$ and $6$ to get $12$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{21}{5}\times \frac{12+1}{6}-\frac{3\times 6+1}{6}}$$

Add $12$ and $1$ to get $13$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{21}{5}\times \frac{13}{6}-\frac{3\times 6+1}{6}}$$

Multiply $\frac{21}{5}$ times $\frac{13}{6}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{21\times 13}{5\times 6}-\frac{3\times 6+1}{6}}$$

Do the multiplications in the fraction $\frac{21\times 13}{5\times 6}$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{273}{30}-\frac{3\times 6+1}{6}}$$

Reduce the fraction $\frac{273}{30}$ to lowest terms by extracting and canceling out $3$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{3}{5}+\frac{91}{10}-\frac{3\times 6+1}{6}}$$

Least common multiple of $5$ and $10$ is $10$. Convert $\frac{3}{5}$ and $\frac{91}{10}$ to fractions with denominator $10$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{6}{10}+\frac{91}{10}-\frac{3\times 6+1}{6}}$$

Since $\frac{6}{10}$ and $\frac{91}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{6+91}{10}-\frac{3\times 6+1}{6}}$$

Add $6$ and $91$ to get $97$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{97}{10}-\frac{3\times 6+1}{6}}$$

Multiply $3$ and $6$ to get $18$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{97}{10}-\frac{18+1}{6}}$$

Add $18$ and $1$ to get $19$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{97}{10}-\frac{19}{6}}$$

Least common multiple of $10$ and $6$ is $30$. Convert $\frac{97}{10}$ and $\frac{19}{6}$ to fractions with denominator $30$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{291}{30}-\frac{95}{30}}$$

Since $\frac{291}{30}$ and $\frac{95}{30}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{291-95}{30}}$$

Subtract $95$ from $291$ to get $196$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{196}{30}}$$

Reduce the fraction $\frac{196}{30}$ to lowest terms by extracting and canceling out $2$.

$$\frac{47}{11}+\frac{\frac{45}{8}}{\frac{98}{15}}$$

Divide $\frac{45}{8}$ by $\frac{98}{15}$ by multiplying $\frac{45}{8}$ by the reciprocal of $\frac{98}{15}$.

$$\frac{47}{11}+\frac{45}{8}\times \frac{15}{98}$$

Multiply $\frac{45}{8}$ times $\frac{15}{98}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{47}{11}+\frac{45\times 15}{8\times 98}$$

Do the multiplications in the fraction $\frac{45\times 15}{8\times 98}$.

$$\frac{47}{11}+\frac{675}{784}$$

Least common multiple of $11$ and $784$ is $8624$. Convert $\frac{47}{11}$ and $\frac{675}{784}$ to fractions with denominator $8624$.

$$\frac{36848}{8624}+\frac{7425}{8624}$$

Since $\frac{36848}{8624}$ and $\frac{7425}{8624}$ have the same denominator, add them by adding their numerators.

$$\frac{36848+7425}{8624}$$

Add $36848$ and $7425$ to get $44273$.

$$\frac{44273}{8624}$$

Show Solution

Factor

$\frac{44273}{2 ^ {4} \cdot 7 ^ {2} \cdot 11} = 5\frac{1153}{8624} = 5.133696660482375$

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