How to solve 3 4 7/10 + 6/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 4 7/10 + 6/8 | Equatix

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$$4 \frac { 7 } { 10 } + \frac { 6 } { 8 }$$

$\frac{109}{20}=5.45$

Multiply $4$ and $10$ to get $40$.

$$\frac{40+7}{10}+\frac{6}{8}$$

Add $40$ and $7$ to get $47$.

$$\frac{47}{10}+\frac{6}{8}$$

Reduce the fraction $\frac{6}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{47}{10}+\frac{3}{4}$$

Least common multiple of $10$ and $4$ is $20$. Convert $\frac{47}{10}$ and $\frac{3}{4}$ to fractions with denominator $20$.

$$\frac{94}{20}+\frac{15}{20}$$

Since $\frac{94}{20}$ and $\frac{15}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{94+15}{20}$$

Add $94$ and $15$ to get $109$.

$$\frac{109}{20}$$

$\frac{109}{2 ^ {2} \cdot 5} = 5\frac{9}{20} = 5.45$