$$4 \frac { x ^ { 3 } - 8 } { x ^ { 2 } + 2 x + 4 } - \frac { x ^ { 3 } + 8 } { x ^ { 2 } - 2 x + 4 }$$
$3x-10$
$$4\times \frac{\left(x-2\right)\left(x^{2}+2x+4\right)}{x^{2}+2x+4}-\frac{x^{3}+8}{x^{2}-2x+4}$$
$$4\left(x-2\right)-\frac{x^{3}+8}{x^{2}-2x+4}$$
$$4x-8-\frac{x^{3}+8}{x^{2}-2x+4}$$
$$4x-8-\frac{\left(x+2\right)\left(x^{2}-2x+4\right)}{x^{2}-2x+4}$$
$$4x-8-\left(x+2\right)$$
$$4x-8-x-2$$
$$3x-8-2$$
$$3x-10$$
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