Solve 4-{-5-9-[-(-5\times-4+6\div-3)-9\times-30\div-6+7]-3}-3\div-3

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Question

$$4- \{ -5-9-[-(-5 \times -4+6 \div -3)-9 \times -30 \div -6+7]-3 \} -3 \div -3$$

Evaluate

$-34$

Solution Steps

Subtract $9$ from $-5$ to get $-14$.

$$4-\left(-14-\left(-\left(-5\left(-4\right)+\frac{6}{-3}\right)-\frac{9\left(-30\right)}{-6}+7\right)-3\right)-\frac{3}{-3}$$

Multiply $-5$ and $-4$ to get $20$.

$$4-\left(-14-\left(-\left(20+\frac{6}{-3}\right)-\frac{9\left(-30\right)}{-6}+7\right)-3\right)-\frac{3}{-3}$$

Divide $6$ by $-3$ to get $-2$.

$$4-\left(-14-\left(-\left(20-2\right)-\frac{9\left(-30\right)}{-6}+7\right)-3\right)-\frac{3}{-3}$$

Subtract $2$ from $20$ to get $18$.

$$4-\left(-14-\left(-18-\frac{9\left(-30\right)}{-6}+7\right)-3\right)-\frac{3}{-3}$$

Multiply $9$ and $-30$ to get $-270$.

$$4-\left(-14-\left(-18-\frac{-270}{-6}+7\right)-3\right)-\frac{3}{-3}$$

Divide $-270$ by $-6$ to get $45$.

$$4-\left(-14-\left(-18-45+7\right)-3\right)-\frac{3}{-3}$$

Subtract $45$ from $-18$ to get $-63$.

$$4-\left(-14-\left(-63+7\right)-3\right)-\frac{3}{-3}$$

Add $-63$ and $7$ to get $-56$.

$$4-\left(-14-\left(-56\right)-3\right)-\frac{3}{-3}$$

The opposite of $-56$ is $56$.

$$4-\left(-14+56-3\right)-\frac{3}{-3}$$

Add $-14$ and $56$ to get $42$.

$$4-\left(42-3\right)-\frac{3}{-3}$$

Subtract $3$ from $42$ to get $39$.

$$4-39-\frac{3}{-3}$$

Subtract $39$ from $4$ to get $-35$.

$$-35-\frac{3}{-3}$$

Divide $3$ by $-3$ to get $-1$.

$$-35-\left(-1\right)$$

The opposite of $-1$ is $1$.

$$-35+1$$

Add $-35$ and $1$ to get $-34$.

$$-34$$

Show Solution

Factor