1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4-1/5 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4-1/5$$

Evaluate

$\frac{19}{5}=3.8$

Solution Steps

Convert $4$ to fraction $\frac{20}{5}$.

$$\frac{20}{5}-\frac{1}{5}$$

Since $\frac{20}{5}$ and $\frac{1}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-1}{5}$$

Subtract $1$ from $20$ to get $19$.

$$\frac{19}{5}$$

Show Solution

Factor

$\frac{19}{5} = 3\frac{4}{5} = 3.8$

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