How to solve 4-5x < -x-2

Q: How to solve 4-5x < -x-2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4-5x < -x-2 | Equatix

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Question

$$4-5x < -x-2$$

Solve for x

$x>\frac{3}{2}$

Solution Steps

Add $x$ to both sides.

$$4-5x+x<-2$$

Combine $-5x$ and $x$ to get $-4x$.

$$4-4x<-2$$

Subtract $4$ from both sides.

$$-4x<-2-4$$

Subtract $4$ from $-2$ to get $-6$.

$$-4x<-6$$

Divide both sides by $-4$. Since $-4$ is negative, the inequality direction is changed.

$$x>\frac{-6}{-4}$$

Reduce the fraction $\frac{-6}{-4}$ to lowest terms by extracting and canceling out $-2$.

$$x>\frac{3}{2}$$

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