$$4-\frac{8}{3x+1}-\frac{3x^{2}+5}{3x+1}$$
$\frac{3\left(1-x\right)\left(x-3\right)}{3x+1}$
$$\frac{4\left(3x+1\right)}{3x+1}-\frac{8}{3x+1}-\frac{3x^{2}+5}{3x+1}$$
$$\frac{4\left(3x+1\right)-8}{3x+1}-\frac{3x^{2}+5}{3x+1}$$
$$\frac{12x+4-8}{3x+1}-\frac{3x^{2}+5}{3x+1}$$
$$\frac{12x-4}{3x+1}-\frac{3x^{2}+5}{3x+1}$$
$$\frac{12x-4-\left(3x^{2}+5\right)}{3x+1}$$
$$\frac{12x-4-3x^{2}-5}{3x+1}$$
$$\frac{12x-9-3x^{2}}{3x+1}$$
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$-\frac{3\left(x^{2}-4x+3\right)}{3x+1}$