How to solve ,4n^ 2 -9n+26=0 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve ,4n^ 2 -9n+26=0 2 | Equatix

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$$4 n ^ { 2 } - 9 x + 26 = 0$$

$x=\frac{4n^{2}+26}{9}$

Subtract $4n^{2}$ from both sides. Anything subtracted from zero gives its negation.

$$-9x+26=-4n^{2}$$

Subtract $26$ from both sides.

$$-9x=-4n^{2}-26$$

Divide both sides by $-9$.

$$\frac{-9x}{-9}=\frac{-4n^{2}-26}{-9}$$

Dividing by $-9$ undoes the multiplication by $-9$.

$$x=\frac{-4n^{2}-26}{-9}$$

Divide $-4n^{2}-26$ by $-9$.

$$x=\frac{4n^{2}+26}{9}$$

$n=-\frac{\sqrt{9x-26}}{2}$
$n=\frac{\sqrt{9x-26}}{2}$

$n=\frac{\sqrt{9x-26}}{2}$
$n=-\frac{\sqrt{9x-26}}{2}\text{, }x\geq \frac{26}{9}$