Question

$$4(2x-5)=3(2x+18); 2(x+5)-8(x-6)=10$$

Answer

No Solution

Solution


Solve for \(x\) in \(4(2x-5)=3(2x+18)\).
\[x=37\]
Substitute \(x=37\) into \(2(x+5)-8(x-6)=10\).
\[-164=10\]
Since \(-164=10\) is not true, this is an inconsistent system.
No Solution