How to solve 4(3/5)-2(7/10)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4(3/5)-2(7/10) | Equatix

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Question

$$4(3/5)-2(7/10)$$

Evaluate

$1$

Solution Steps

Express $4\times \frac{3}{5}$ as a single fraction.

$$\frac{4\times 3}{5}-2\times \frac{7}{10}$$

Multiply $4$ and $3$ to get $12$.

$$\frac{12}{5}-2\times \frac{7}{10}$$

Express $2\times \frac{7}{10}$ as a single fraction.

$$\frac{12}{5}-\frac{2\times 7}{10}$$

Multiply $2$ and $7$ to get $14$.

$$\frac{12}{5}-\frac{14}{10}$$

Reduce the fraction $\frac{14}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{12}{5}-\frac{7}{5}$$

Since $\frac{12}{5}$ and $\frac{7}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-7}{5}$$

Subtract $7$ from $12$ to get $5$.

$$\frac{5}{5}$$

Divide $5$ by $5$ to get $1$.

$$1$$

Show Solution

Factor

$1$