How to solve 4(6x+3)+5(2x-1)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4(6x+3)+5(2x-1) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4(6x+3)+5(2x-1)$$

Evaluate

$34x+7$

Solution Steps

Use the distributive property to multiply $4$ by $6x+3$.

$$24x+12+5\left(2x-1\right)$$

Use the distributive property to multiply $5$ by $2x-1$.

$$24x+12+10x-5$$

Combine $24x$ and $10x$ to get $34x$.

$$34x+12-5$$

Subtract $5$ from $12$ to get $7$.

$$34x+7$$

Show Solution

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$34x+7$

Solution Steps

Use the distributive property to multiply $4$ by $6x+3$.

$$24x+12+5\left(2x-1\right)$$

Use the distributive property to multiply $5$ by $2x-1$.

$$24x+12+10x-5$$

Combine $24x$ and $10x$ to get $34x$.

$$34x+12-5$$

Subtract $5$ from $12$ to get $7$.

$$34x+7$$

Show Solution

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Question

Evaluate

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Solution Steps