Solve 4(7 + 3x) - 5(6 - 2x) + 1 = 8(1 + 4x) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4(7+3x)-5(6-2x)+1=8(1+4x)$$

Solve for x

$x=-\frac{9}{10}=-0.9$

Steps for Solving Linear Equation

Use the distributive property to multiply $4$ by $7+3x$.

$$28+12x-5\left(6-2x\right)+1=8\left(1+4x\right)$$

Use the distributive property to multiply $-5$ by $6-2x$.

$$28+12x-30+10x+1=8\left(1+4x\right)$$

Subtract $30$ from $28$ to get $-2$.

$$-2+12x+10x+1=8\left(1+4x\right)$$

Combine $12x$ and $10x$ to get $22x$.

$$-2+22x+1=8\left(1+4x\right)$$

Add $-2$ and $1$ to get $-1$.

$$-1+22x=8\left(1+4x\right)$$

Use the distributive property to multiply $8$ by $1+4x$.

$$-1+22x=8+32x$$

Subtract $32x$ from both sides.

$$-1+22x-32x=8$$

Combine $22x$ and $-32x$ to get $-10x$.

$$-1-10x=8$$

Add $1$ to both sides.

$$-10x=8+1$$

Add $8$ and $1$ to get $9$.

$$-10x=9$$

Divide both sides by $-10$.

$$x=\frac{9}{-10}$$

Fraction $\frac{9}{-10}$ can be rewritten as $-\frac{9}{10}$ by extracting the negative sign.

$$x=-\frac{9}{10}$$