Solve 4(R - 3) = q(1 - R) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4(R-3)=q(1-R)$$

Solve for R

$R=\frac{q+12}{q+4}$
$q\neq -4$

Steps for Solving Linear Equation

Use the distributive property to multiply $4$ by $R-3$.

$$4R-12=q\left(1-R\right)$$

Use the distributive property to multiply $q$ by $1-R$.

$$4R-12=q-qR$$

Add $qR$ to both sides.

$$4R-12+qR=q$$

Add $12$ to both sides.

$$4R+qR=q+12$$

Combine all terms containing $R$.

$$\left(4+q\right)R=q+12$$

The equation is in standard form.

$$\left(q+4\right)R=q+12$$

Divide both sides by $q+4$.

$$\frac{\left(q+4\right)R}{q+4}=\frac{q+12}{q+4}$$

Dividing by $q+4$ undoes the multiplication by $q+4$.

$$R=\frac{q+12}{q+4}$$

Solve for q

$q=-\frac{4\left(R-3\right)}{R-1}$
$R\neq 1$

Steps for Solving Linear Equation

Use the distributive property to multiply $4$ by $R-3$.

$$4R-12=q\left(1-R\right)$$

Use the distributive property to multiply $q$ by $1-R$.

$$4R-12=q-qR$$

Swap sides so that all variable terms are on the left hand side.

$$q-qR=4R-12$$

Combine all terms containing $q$.

$$\left(1-R\right)q=4R-12$$

Divide both sides by $1-R$.

$$\frac{\left(1-R\right)q}{1-R}=\frac{4R-12}{1-R}$$

Dividing by $1-R$ undoes the multiplication by $1-R$.

$$q=\frac{4R-12}{1-R}$$

Divide $-12+4R$ by $1-R$.

$$q=\frac{4\left(R-3\right)}{1-R}$$