How to solve 4(x+2) <= 4x+8

Q: How to solve 4(x+2) <= 4x+8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4(x+2) <= 4x+8 | Equatix

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3(r+2s)=2t-4

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Question

$$4(x+2) \leq 4x+8$$

Solve for x

$x\in \mathrm{R}$

Solution Steps

Use the distributive property to multiply $4$ by $x+2$.

$$4x+8\leq 4x+8$$

Subtract $4x$ from both sides.

$$4x+8-4x\leq 8$$

Combine $4x$ and $-4x$ to get $0$.

$$8\leq 8$$

This is true for any $x$.

$$x\in \mathrm{R}$$

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Solve for x

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