How to solve |4|+|-3|-|5|-|-6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve |4|+|-3|-|5|-|-6 | Equatix

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Question

$$|4|+|-3|-|5|-|-6$$

Evaluate

$-4$

Solution Steps

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $4$ is $4$.

$$4+|-3|-|5|-|-6|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-3$ is $3$.

$$4+3-|5|-|-6|$$

Add $4$ and $3$ to get $7$.

$$7-|5|-|-6|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $5$ is $5$.

$$7-5-|-6|$$

Subtract $5$ from $7$ to get $2$.

$$2-|-6|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-6$ is $6$.

$$2-6$$

Subtract $6$ from $2$ to get $-4$.

$$-4$$

Show Solution

Factor