How to solve 4 + 1 - 2; 6 * 12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4 + 1 - 2; 6 * 12 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4+1-2; +6\times12$$

Sort

$3,\ 72$

Solution Steps

Add $4$ and $1$ to get $5$.

$$sort(5-2,6\times 12)$$

Subtract $2$ from $5$ to get $3$.

$$sort(3,6\times 12)$$

Multiply $6$ and $12$ to get $72$.

$$sort(3,72)$$

The list values are already in order.

$$3,72$$

Show Solution

Evaluate

$3,\ 72$

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