$$4+12 \times 15-(-3)+8 \div 6$$
$\frac{565}{3}\approx 188.333333333$
$$4+180-\left(-3\right)+\frac{8}{6}$$
$$184-\left(-3\right)+\frac{8}{6}$$
$$184+3+\frac{8}{6}$$
$$187+\frac{8}{6}$$
$$187+\frac{4}{3}$$
$$\frac{561}{3}+\frac{4}{3}$$
$$\frac{561+4}{3}$$
$$\frac{565}{3}$$
Show Solution
Hide Solution
$\frac{5 \cdot 113}{3} = 188\frac{1}{3} = 188.33333333333334$
