How to solve 4+3(9-3+4+6)-7+11

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4+3(9-3+4+6)-7+11 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4+3(9-3+4+6)-7+11$$

Evaluate

$56$

Solution Steps

Subtract $3$ from $9$ to get $6$.

$$4+3\left(6+4+6\right)-7+11$$

Add $6$ and $4$ to get $10$.

$$4+3\left(10+6\right)-7+11$$

Add $10$ and $6$ to get $16$.

$$4+3\times 16-7+11$$

Multiply $3$ and $16$ to get $48$.

$$4+48-7+11$$

Add $4$ and $48$ to get $52$.

$$52-7+11$$

Subtract $7$ from $52$ to get $45$.

$$45+11$$

Add $45$ and $11$ to get $56$.

$$56$$

Show Solution

Factor

$2^{3}\times 7$

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