How to solve 4+(3)/(5)-(7)/(8)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4+(3)/(5)-(7)/(8) | Equatix

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$$4+ \frac{ 3 }{ 5 } - \frac{ 7 }{ 8 }$$

$\frac{149}{40}=3.725$

Convert $4$ to fraction $\frac{20}{5}$.

$$\frac{20}{5}+\frac{3}{5}-\frac{7}{8}$$

Since $\frac{20}{5}$ and $\frac{3}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{20+3}{5}-\frac{7}{8}$$

Add $20$ and $3$ to get $23$.

$$\frac{23}{5}-\frac{7}{8}$$

Least common multiple of $5$ and $8$ is $40$. Convert $\frac{23}{5}$ and $\frac{7}{8}$ to fractions with denominator $40$.

$$\frac{184}{40}-\frac{35}{40}$$

Since $\frac{184}{40}$ and $\frac{35}{40}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{184-35}{40}$$

Subtract $35$ from $184$ to get $149$.

$$\frac{149}{40}$$

$\frac{149}{2 ^ {3} \cdot 5} = 3\frac{29}{40} = 3.725$