$$4 \times (-6) \div (- \frac{ 4 }{ 3 } )$$
$18$
$$\frac{-24}{-\frac{4}{3}}$$
$$-24\left(-\frac{3}{4}\right)$$
$$\frac{-24\left(-3\right)}{4}$$
$$\frac{72}{4}$$
$$18$$
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$2\times 3^{2}$
