Question

$$4 x + 2 x + 3 y - 12 - 9 y = 6 + 6 x + 6 x + 8 x ^ { 3 } + 2 x ^ { 2 } + 2 y ^ { 2 } =$$

Solve for x

$x=\frac{\sqrt[3]{6\sqrt{1296y^{4}+7776y^{3}+34356y^{2}+68076y+100521}-216y^{2}-648y-1891}+\sqrt[3]{-6\sqrt{1296y^{4}+7776y^{3}+34356y^{2}+68076y+100521}-216y^{2}-648y-1891}-1}{12}$

Solve for y

$y=\frac{-\sqrt{-16x^{3}-4x^{2}-12x-27}-3}{2}$
$y=\frac{\sqrt{-16x^{3}-4x^{2}-12x-27}-3}{2}\text{, }-16x^{3}-4x^{2}-12x-27\geq 0$