How to solve + их -2-6к + 3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve + их -2-6к + 3 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$4 x ^ { 2 } + \frac { 1 } { 4 x } - 2 - 6 x + 3$$

$4x^{2}-6x+1+\frac{1}{4x}$

Add $-2$ and $3$ to get $1$.

$$4x^{2}+\frac{1}{4x}+1-6x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $4x^{2}+1-6x$ times $\frac{4x}{4x}$.

$$\frac{\left(4x^{2}+1-6x\right)\times 4x}{4x}+\frac{1}{4x}$$

Since $\frac{\left(4x^{2}+1-6x\right)\times 4x}{4x}$ and $\frac{1}{4x}$ have the same denominator, add them by adding their numerators.

$$\frac{\left(4x^{2}+1-6x\right)\times 4x+1}{4x}$$

Do the multiplications in $\left(4x^{2}+1-6x\right)\times 4x+1$.

$$\frac{16x^{3}+4x-24x^{2}+1}{4x}$$

$\frac{16x^{3}-24x^{2}+4x+1}{4x}$