How to solve 40/26-2/14

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 40/26-2/14 | Equatix

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$$40/26-2/14$$

$\frac{127}{91}\approx 1.395604396$

Reduce the fraction $\frac{40}{26}$ to lowest terms by extracting and canceling out $2$.

$$\frac{20}{13}-\frac{2}{14}$$

Reduce the fraction $\frac{2}{14}$ to lowest terms by extracting and canceling out $2$.

$$\frac{20}{13}-\frac{1}{7}$$

Least common multiple of $13$ and $7$ is $91$. Convert $\frac{20}{13}$ and $\frac{1}{7}$ to fractions with denominator $91$.

$$\frac{140}{91}-\frac{13}{91}$$

Since $\frac{140}{91}$ and $\frac{13}{91}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{140-13}{91}$$

Subtract $13$ from $140$ to get $127$.

$$\frac{127}{91}$$

$\frac{127}{7 \cdot 13} = 1\frac{36}{91} = 1.3956043956043955$