How to solve 40+1/15 imes20

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 40+1/15\times20 | Equatix

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$$40+1/15 \times 20$$

$\frac{124}{3}\approx 41.333333333$

Multiply $\frac{1}{15}$ and $20$ to get $\frac{20}{15}$.

$$40+\frac{20}{15}$$

Reduce the fraction $\frac{20}{15}$ to lowest terms by extracting and canceling out $5$.

$$40+\frac{4}{3}$$

Convert $40$ to fraction $\frac{120}{3}$.

$$\frac{120}{3}+\frac{4}{3}$$

Since $\frac{120}{3}$ and $\frac{4}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{120+4}{3}$$

Add $120$ and $4$ to get $124$.

$$\frac{124}{3}$$

$\frac{2 ^ {2} \cdot 31}{3} = 41\frac{1}{3} = 41.333333333333336$