How to solve 40(7 + 11/60)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 40(7 + 11/60) | Equatix

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$$40\times(7+\frac{11}{60})$$

$\frac{862}{3}\approx 287.333333333$

Convert $7$ to fraction $\frac{420}{60}$.

$$40\left(\frac{420}{60}+\frac{11}{60}\right)$$

Since $\frac{420}{60}$ and $\frac{11}{60}$ have the same denominator, add them by adding their numerators.

$$40\times \frac{420+11}{60}$$

Add $420$ and $11$ to get $431$.

$$40\times \frac{431}{60}$$

Express $40\times \frac{431}{60}$ as a single fraction.

$$\frac{40\times 431}{60}$$

Multiply $40$ and $431$ to get $17240$.

$$\frac{17240}{60}$$

Reduce the fraction $\frac{17240}{60}$ to lowest terms by extracting and canceling out $20$.

$$\frac{862}{3}$$

$\frac{2 \cdot 431}{3} = 287\frac{1}{3} = 287.3333333333333$