1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 41+9/5 | Equatix

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3(r+2s)=2t-4

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Question

$$41+9/5$$

Evaluate

$\frac{214}{5}=42.8$

Solution Steps

Convert $41$ to fraction $\frac{205}{5}$.

$$\frac{205}{5}+\frac{9}{5}$$

Since $\frac{205}{5}$ and $\frac{9}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{205+9}{5}$$

Add $205$ and $9$ to get $214$.

$$\frac{214}{5}$$

Show Solution

Factor

$\frac{2 \cdot 107}{5} = 42\frac{4}{5} = 42.8$

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