How to solve c ) 4100 by 681

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve c ) 4100 by 681 | Equatix

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Question

$$4100 681$$

Evaluate

$2792100$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}4100\\\underline{\times\phantom{9999}681}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 4100 with 1. Write the result 4100 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}4100\\\underline{\times\phantom{9999}681}\\\phantom{\times999}4100\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 4100 with 8. Write the result 32800 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}4100\\\underline{\times\phantom{9999}681}\\\phantom{\times999}4100\\\phantom{\times9}32800\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 4100 with 6. Write the result 24600 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}4100\\\underline{\times\phantom{9999}681}\\\phantom{\times999}4100\\\phantom{\times9}32800\phantom{9}\\\underline{\phantom{\times}24600\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{2}\times 3\times 5^{2}\times 41\times 227$