How to solve 412 imes530

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 412\times530 | Equatix

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Question

$$412 \times 530$$

Evaluate

$218360$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}412\\\underline{\times\phantom{999}530}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 412 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}412\\\underline{\times\phantom{999}530}\\\phantom{\times999999}0\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 412 with 3. Write the result 1236 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}412\\\underline{\times\phantom{999}530}\\\phantom{\times999999}0\\\phantom{\times9}1236\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 412 with 5. Write the result 2060 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}412\\\underline{\times\phantom{999}530}\\\phantom{\times999999}0\\\phantom{\times9}1236\phantom{9}\\\underline{\phantom{\times}2060\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}412\\\underline{\times\phantom{999}530}\\\phantom{\times999999}0\\\phantom{\times9}1236\phantom{9}\\\underline{\phantom{\times}2060\phantom{99}}\\\phantom{\times}218360\end{array}$$

Show Solution

Factor

$2^{3}\times 5\times 53\times 103$