$$413Y-287X+69z=26522$$
$X=\frac{59Y}{41}+\frac{69z}{287}-\frac{26522}{287}$
$$-287X+69z=26522-413Y$$
$$-287X=26522-413Y-69z$$
$$\frac{-287X}{-287}=\frac{26522-413Y-69z}{-287}$$
$$X=\frac{26522-413Y-69z}{-287}$$
$$X=\frac{59Y}{41}+\frac{69z}{287}-\frac{26522}{287}$$
Show Solution
Hide Solution
$Y=\frac{41X}{59}-\frac{69z}{413}+\frac{26522}{413}$
$$413Y+69z=26522+287X$$
$$413Y=26522+287X-69z$$
$$\frac{413Y}{413}=\frac{26522+287X-69z}{413}$$
$$Y=\frac{26522+287X-69z}{413}$$
$$Y=\frac{41X}{59}-\frac{69z}{413}+\frac{26522}{413}$$
