How to solve 426 imes62

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 426\times62 | Equatix

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Question

$$426 \times 62$$

Evaluate

$26412$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}426\\\underline{\times\phantom{999}62}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 426 with 2. Write the result 852 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}426\\\underline{\times\phantom{999}62}\\\phantom{\times99}852\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 426 with 6. Write the result 2556 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}426\\\underline{\times\phantom{999}62}\\\phantom{\times99}852\\\underline{\phantom{\times}2556\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}426\\\underline{\times\phantom{999}62}\\\phantom{\times99}852\\\underline{\phantom{\times}2556\phantom{9}}\\\phantom{\times}26412\end{array}$$

Show Solution

Factor

$2^{2}\times 3\times 31\times 71$