How to solve 428 imes38352

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 428\times38352 | Equatix

Question

$$428 \times 38352$$

Evaluate

$16414656$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99999}428\\\underline{\times\phantom{999}38352}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 428 with 2. Write the result 856 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99999}428\\\underline{\times\phantom{999}38352}\\\phantom{\times99999}856\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 428 with 5. Write the result 2140 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99999}428\\\underline{\times\phantom{999}38352}\\\phantom{\times99999}856\\\phantom{\times999}2140\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 428 with 3. Write the result 1284 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99999}428\\\underline{\times\phantom{999}38352}\\\phantom{\times99999}856\\\phantom{\times999}2140\phantom{9}\\\phantom{\times99}1284\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 428 with 8. Write the result 3424 at the end leaving 3 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99999}428\\\underline{\times\phantom{999}38352}\\\phantom{\times99999}856\\\phantom{\times999}2140\phantom{9}\\\phantom{\times99}1284\phantom{99}\\\phantom{\times9}3424\phantom{999}\\\end{array}$$

Now multiply the first number with the $5^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 428 with 3. Write the result 1284 at the end leaving 4 spaces to the right like this.

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{6}\times 3\times 17\times 47\times 107$

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Steps For Long Multiplication

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