How to solve 4298 imes58

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4298\times58 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$4298 \times 58$$

Evaluate

$249284$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}4298\\\underline{\times\phantom{9999}58}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 4298 with 8. Write the result 34384 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}4298\\\underline{\times\phantom{9999}58}\\\phantom{\times9}34384\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 4298 with 5. Write the result 21490 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}4298\\\underline{\times\phantom{9999}58}\\\phantom{\times9}34384\\\underline{\phantom{\times}21490\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}4298\\\underline{\times\phantom{9999}58}\\\phantom{\times9}34384\\\underline{\phantom{\times}21490\phantom{9}}\\\phantom{\times}249284\end{array}$$

Show Solution

Factor

$2^{2}\times 7\times 29\times 307$