How to solve 45/23+25/18+15/4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 45/23+25/18+15/4 | Equatix

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$$45/23+25/18+15/4$$

$\frac{5875}{828}\approx 7.095410628$

Least common multiple of $23$ and $18$ is $414$. Convert $\frac{45}{23}$ and $\frac{25}{18}$ to fractions with denominator $414$.

$$\frac{810}{414}+\frac{575}{414}+\frac{15}{4}$$

Since $\frac{810}{414}$ and $\frac{575}{414}$ have the same denominator, add them by adding their numerators.

$$\frac{810+575}{414}+\frac{15}{4}$$

Add $810$ and $575$ to get $1385$.

$$\frac{1385}{414}+\frac{15}{4}$$

Least common multiple of $414$ and $4$ is $828$. Convert $\frac{1385}{414}$ and $\frac{15}{4}$ to fractions with denominator $828$.

$$\frac{2770}{828}+\frac{3105}{828}$$

Since $\frac{2770}{828}$ and $\frac{3105}{828}$ have the same denominator, add them by adding their numerators.

$$\frac{2770+3105}{828}$$

Add $2770$ and $3105$ to get $5875$.

$$\frac{5875}{828}$$

$\frac{5 ^ {3} \cdot 47}{2 ^ {2} \cdot 3 ^ {2} \cdot 23} = 7\frac{79}{828} = 7.095410628019324$