How to solve 45/23+25/18+15/42

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 45/23+25/18+15/42 | Equatix

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Question

$$45/23+25/18+15/42$$

Evaluate

$\frac{5365}{1449}\approx 3.702553485$

Solution Steps

Least common multiple of $23$ and $18$ is $414$. Convert $\frac{45}{23}$ and $\frac{25}{18}$ to fractions with denominator $414$.

$$\frac{810}{414}+\frac{575}{414}+\frac{15}{42}$$

Since $\frac{810}{414}$ and $\frac{575}{414}$ have the same denominator, add them by adding their numerators.

$$\frac{810+575}{414}+\frac{15}{42}$$

Add $810$ and $575$ to get $1385$.

$$\frac{1385}{414}+\frac{15}{42}$$

Reduce the fraction $\frac{15}{42}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1385}{414}+\frac{5}{14}$$

Least common multiple of $414$ and $14$ is $2898$. Convert $\frac{1385}{414}$ and $\frac{5}{14}$ to fractions with denominator $2898$.

$$\frac{9695}{2898}+\frac{1035}{2898}$$

Since $\frac{9695}{2898}$ and $\frac{1035}{2898}$ have the same denominator, add them by adding their numerators.

$$\frac{9695+1035}{2898}$$

Add $9695$ and $1035$ to get $10730$.

$$\frac{10730}{2898}$$

Reduce the fraction $\frac{10730}{2898}$ to lowest terms by extracting and canceling out $2$.

$$\frac{5365}{1449}$$

Show Solution

Factor

$\frac{5 \cdot 29 \cdot 37}{3 ^ {2} \cdot 7 \cdot 23} = 3\frac{1018}{1449} = 3.7025534851621806$