$$45\div3[90\div2\{6+3(17-14)\}]$$
$10125$
$$15\times \frac{90}{2}\left(6+3\left(17-14\right)\right)$$
$$15\times 45\left(6+3\left(17-14\right)\right)$$
$$675\left(6+3\left(17-14\right)\right)$$
$$675\left(6+3\times 3\right)$$
$$675\left(6+9\right)$$
$$675\times 15$$
$$10125$$
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$3^{4}\times 5^{3}$