1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4741 | Equatix - Math Solver

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$47 ^ { \circ } \times 41 ^ { \circ }$$

Evaluate

$1927$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}47\\\underline{\times\phantom{99}41}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 47 with 1. Write the result 47 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}47\\\underline{\times\phantom{99}41}\\\phantom{\times99}47\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 47 with 4. Write the result 188 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}47\\\underline{\times\phantom{99}41}\\\phantom{\times99}47\\\underline{\phantom{\times}188\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}47\\\underline{\times\phantom{99}41}\\\phantom{\times99}47\\\underline{\phantom{\times}188\phantom{9}}\\\phantom{\times}1927\end{array}$$

Show Solution

Factor

$41\times 47$