Question

$$47275+54 \displaystyle\frac{d}{d \left(6+2 \infty \right) } \infty =$$

Answer

$$47275+54*IM*d*f^2*(6+2*o^2,o^2)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[47275+54d\imath ff(6+2{o}^{2},oo)\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[47275+54d\imath ff(6+2{o}^{2},{o}^{2})\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[47275+54d\imath {f}^{2}(6+2{o}^{2},{o}^{2})\]
Regroup terms.
\[47275+54\imath d{f}^{2}(6+2{o}^{2},{o}^{2})\]