How to solve 473256 by 99

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 473256 by 99 | Equatix

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Question

$$473256 99$$

Evaluate

$46852344$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}473256\\\underline{\times\phantom{999999}99}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 473256 with 9. Write the result 4259304 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}473256\\\underline{\times\phantom{999999}99}\\\phantom{\times9}4259304\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 473256 with 9. Write the result 4259304 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}473256\\\underline{\times\phantom{999999}99}\\\phantom{\times9}4259304\\\underline{\phantom{\times}4259304\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}473256\\\underline{\times\phantom{999999}99}\\\phantom{\times9}4259304\\\underline{\phantom{\times}4259304\phantom{9}}\\\phantom{\times}46852344\end{array}$$

Show Solution

Factor

$2^{3}\times 3^{5}\times 7\times 11\times 313$