Solve 48/[3+15/\ u+10-(3-13)<=] | Equatix

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Question

$$48\div[3+15\div\{u+10-(3-13)\le]$$

Evaluate

$\frac{384}{29}\approx 13.24137931$

Solution Steps

Add $4$ and $10$ to get $14$.

$$\frac{48}{3+\frac{15}{14-\left(3-13\right)}}$$

Subtract $13$ from $3$ to get $-10$.

$$\frac{48}{3+\frac{15}{14-\left(-10\right)}}$$

The opposite of $-10$ is $10$.

$$\frac{48}{3+\frac{15}{14+10}}$$

Add $14$ and $10$ to get $24$.

$$\frac{48}{3+\frac{15}{24}}$$

Reduce the fraction $\frac{15}{24}$ to lowest terms by extracting and canceling out $3$.

$$\frac{48}{3+\frac{5}{8}}$$

Convert $3$ to fraction $\frac{24}{8}$.

$$\frac{48}{\frac{24}{8}+\frac{5}{8}}$$

Since $\frac{24}{8}$ and $\frac{5}{8}$ have the same denominator, add them by adding their numerators.

$$\frac{48}{\frac{24+5}{8}}$$

Add $24$ and $5$ to get $29$.

$$\frac{48}{\frac{29}{8}}$$

Divide $48$ by $\frac{29}{8}$ by multiplying $48$ by the reciprocal of $\frac{29}{8}$.

$$48\times \frac{8}{29}$$

Express $48\times \frac{8}{29}$ as a single fraction.

$$\frac{48\times 8}{29}$$

Multiply $48$ and $8$ to get $384$.

$$\frac{384}{29}$$

Show Solution

Factor

$\frac{2 ^ {7} \cdot 3}{29} = 13\frac{7}{29} = 13.241379310344827$